2x^2-8x+40=0

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Solution for 2x^2-8x+40=0 equation:


Simplifying
2x2 + -8x + 40 = 0

Reorder the terms:
40 + -8x + 2x2 = 0

Solving
40 + -8x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(20 + -4x + x2) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(20 + -4x + x2)' equal to zero and attempt to solve: Simplifying 20 + -4x + x2 = 0 Solving 20 + -4x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-20' to each side of the equation. 20 + -4x + -20 + x2 = 0 + -20 Reorder the terms: 20 + -20 + -4x + x2 = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -4x + x2 = 0 + -20 -4x + x2 = 0 + -20 Combine like terms: 0 + -20 = -20 -4x + x2 = -20 The x term is -4x. Take half its coefficient (-2). Square it (4) and add it to both sides. Add '4' to each side of the equation. -4x + 4 + x2 = -20 + 4 Reorder the terms: 4 + -4x + x2 = -20 + 4 Combine like terms: -20 + 4 = -16 4 + -4x + x2 = -16 Factor a perfect square on the left side: (x + -2)(x + -2) = -16 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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